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'链接已经复制到剪贴板');" type="submit"> <em>复制链接推荐给好友</em></button> <input type="text" class="px vm" onclick="this.select();setCopy(this.value, '链接已经复制到剪贴板');" value="http://www.oecr.com/plugin.php?id=attachcenter:page&aid=9412" size="50" /></p> </div> <div class="bm"> <div class="bm_c xld"> <b>请教光电二极管2CU系列光电流问题:</b><div class="postmsg"><p>我按网上的一个电路图做了一个光度计,线路是正确的,可是我想得到电压值,不知道怎么计算,今天问我们老师,他说我应该查下光电二极管2CU系列光电流和光照的表格,查找光电流值,可是我又找不到那个表格,我想请问下这个输出电压怎么计算啊(我已上传文件),只能查表格的话哪本书上能找到那个表格啊,谢谢您的答复</p><p>电路我改动过,光电二极管用3mm的2cu系列,三极管用9018,放大器用5532p</p><p></p><p><br/></p></div> <div class="postmsg"><p>看不到图。</p><p>我有两个2CU系列的，但表现太差了，灵敏度大约在别的光电管的1/100以下，劝你别用了。</p><p>找那种看起来接收面积大、没有放大凸透镜的那种。</p><p>光电流一般可以计算出来，按照最灵敏的红外部分，大约是每瓦0.6A。</p><p>当然，如果你只做可见光的，需要所谓蓝光的光电管，或者自己加红外改正滤镜。</p><p>最后，别用什么三极管，那东西线性不好。最好用CMOS输入的单端运放，5532p也不合适（还贵）。</p></div> <div class="postmsg">dasd no money no money no money no money no money no money</div> <div class="postmsg">no money no money no money no money no money no money no money no 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